I need some help with this question. I think I got it but need steps to double check and make sure I understand it. Thanks. "The square of an integer has the form 4k or 4k+1 for some integer k. Prove or disprove the statement."
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Originally Posted by Kitizhi I think I got it Awesome!! Let's see your work and hear your ideas.
assume k^2 = n for some integer of k if even n = 2k by def so.. n^2 = (2k)^2 n^2 = 4k^2 n^2 = 4n if odd n = 2k+1 by def so.. n^2=(2k+1) n^2=4k^2+1 n=4n+1 is that correct? i aint really too sure but i kinda makes sense to me
can someone verfiy for me if I am correct please
Looks good to me!
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