1. ## cant solve this problem (proof by contradiction)

i tried to solve this question 100 times but could n't get the right answer
plz help guys

2. $\begin{array}{llr}
1 & {\left( {S \wedge R} \right) \to Q} & {} \\
2 & {\neg R \to \neg P} & {} \\
3 & {S \wedge P} & {} \\
4 & {\neg Q} & {\text{assume}} \\

\end{array}$

$
\begin{array}{llr}
5 & {\neg \left( {S \wedge R} \right)} & {1,4} \\
6 & {\neg S \vee \neg R} & 5 \\
7 & S & 3 \\
8 & {\neg R} & 6 \\
9 & {\neg P} & {2,8} \\
{10} & P & 3 \\
{} & {P \wedge \neg P} & {8,9 \text{ contradiction}} \\ \end{array}$