This is how & works:

&(19, 14) = (5, 0) and &(12, 15) = (0, 3)

How do I show &^2 = &

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- Feb 27th 2009, 12:39 AMjzelltProve this function equation
This is how & works:

&(19, 14) = (5, 0) and &(12, 15) = (0, 3)

How do I show &^2 = & - Feb 27th 2009, 01:02 AMJameson
I'm going to guess that the general form of this is: &(a,b)=(a-b,0) (when a>b) and &(a,b)=(0,b-a) (when b>a). &^2 doesn't make sense to me since & is being defined as an operation on two numbers a,b and means nothing by itself thus can't be squared. Can you explain more please?

- Feb 27th 2009, 05:25 AMmr fantastic