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Math Help - computing sets

  1. #1
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    computing sets

    Can someone help me out with the following question?

    A= {1,3,5,6} and B={3,5} and C={a,b,c}

    Compute:

    a. A-B = {1,6}
    b. B X C ( X meaning Cartesian Product) {(3,a),(3,b),(3,c),(5,a),(5,b),(5,c)}
    c. A A\cap B (B-A)
    d. A A\Delta B {1,6}

    can anyone help me with 3.
    Last edited by wonderstrike; February 24th 2009 at 03:41 PM.
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  2. #2
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    Quote Originally Posted by wonderstrike View Post
    A= {1,3,5,6} and B={3,5} and C={a,b,c}
    Compute:
    a. A-B
    b. B X C ( X meaning Cartesian Product) * this one confuses the heck outta me
    c. A Intersection (B-A)
    d. A symmetric difference B
    ps, how do I do the upside down U and symetric difference signs?
    [tex]A\cap B[/tex] gives A\cap B
    [tex]A\cup B[/tex] gives A\cup B
    [tex]A \times B[/tex] gives A \times B
    [tex]A\Delta B[/tex] gives A\Delta B symmetric difference.
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  3. #3
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    Can I have help with c.

    the way I understand is i need to do (B-A) 1st.

    Well B-A is leaving me with nothing...
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  4. #4
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    A \cap \left( {B\backslash A} \right) = A \cap \left( {B \cap A^c } \right) = \emptyset

    [tex]A^c[/matH] is the complement of A, all elements not in A.
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  5. #5
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    Quote Originally Posted by Plato View Post
    A \cap \left( {B\backslash A} \right) = A \cap \left( {B \cap A^c } \right) = \emptyset

    A^c is the complement of A, all elements not in A.
    Right.. so \emptyset means that they are disjoint right?
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