There is a theorem: .
Hi,
I've a doubt about his : True or false? : If then or is not invertible.
I know that or but there is also the possible case and . So I'm tempted to answer False.
Because they say while the answer could be . So does the include the case?
I know I don't explain myself well. You can answer the question true or false and I will understand. Thank you very much.
Yes I know! ahahah. Sorry, I wasn't clear AT ALL.
My answer would be that if , then or or or and .
It's exactly the same as this case : (a-b)(z-y)=0. We have that or (a-b)=0 or (z-y)=0. But what I'm trying to say is that there is also the case " (a-b)=0 and (z-y)=0 ".
I'm not sure I'm explaining well. That's why I'd like you or whoever who is sure and certain, to answer the "true or false" question. For me it would be false, because there could be the case and which is not included in the phrase "det A=0 or det B=0", which I interpret as "it's either det A=0 or det B=0, but not both at the same time". So basically I'm asking if I'm not interpreting things badly.