P(n) = n^2+1, write P(m-1) and is it prime?
That is the last part of the question for my homework. I have done P(1) . . P(6). I'm just not sure how to work this one out.
I got ((m-1)^2)+1.
Any help would be appreciated. Thanks
I dont really understood the questionIf P(n) is "n^2+1 is prime" write p(1), p(2) and p(12). which if any is true? also, write P(m-1).
What does any stand for , its not true for n=3 ,12.....and many other numbers
Incase we are reqired to prove that if its true for n than its also true for (n-1) by induction than
its not true for n=10
But here is what I could guess
Whenever its true for any of the number "m" we need to find P(m-1)
So the answers are
P(1-1) = 1
P(2-1) = 1^2+1 = 2
.
.
But we need not find
P(12-1) because
P(12) = 144+1 = 145 is not a prime
I dont know where is mathematical induction involved in this