Finding a term in a Binomial Expansion

**AlgebraicallyChallenged** · February 11th 2009, 04:56 PM

Good evening forum I am having a problem with the following problem any help would be appreciated:

thank you , AC

**Jhevon** · February 11th 2009, 06:07 PM

Originally Posted by AlgebraicallyChallenged

Good evening forum I am having a problem with the following problem any help would be appreciated:

thank you , AC

use the binomial expansion formula for $(x + y)^8$

we have $(x + y)^8 = \sum_{k = 0}^8 {8 \choose k}x^{8 - k}y^k$

if we choose $x = a$ and $y = -b^3$ we realize that we want the term where we have $y^3$ ...that's where k = 3

this is the term ${8 \choose 3}x^5y^3$

note that ${n \choose k} = _nC_k = \frac {n!}{k!(n - k)!}$

**skeeter** · February 11th 2009, 06:10 PM

Originally Posted by AlgebraicallyChallenged

Good evening forum I am having a problem with the following problem any help would be appreciated:

thank you , AC

$(a-b^3)^8 = {8\choose0}a^8 + {8\choose1}a^7(-b^3) + {8\choose2}a^6(-b^3)^2 + {8\choose3}a^5(-b^3)^3 + ...$

see the term you need to find?

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