It says we need to use the theorem

"The union of a finite or countable number of countable sets A1,A2,... is itself countable." &

"The set of real numbers in the closed unit interval [0,1] is uncountable."

- February 3rd 2009, 10:44 AMninano1205Prove the existence of uncountably many transcendental numbers
It says we need to use the theorem

"The union of a finite or countable number of countable sets A1,A2,... is itself countable." &

"The set of real numbers in the closed unit interval [0,1] is uncountable." - February 3rd 2009, 10:58 AMThePerfectHacker
Here is a hint. All algebraic numbers are roots of non-zero polynomials with rational coefficient. There are countable many non-zero polynomials with rational coefficients and each of these polynomials has finitely many zeros. This means that the cardinality of the algebraic numbers is countable. Can you see what to do next?

- February 3rd 2009, 11:31 AMninano1205Sounds right?
The set of real numbers is a union of Algebraic numbers and transcendental numbers and uncountable. The set of Algebraic numbers is countable. Therefore the set of transcendental numbers should be uncountable, otherwise the set of real numbers would be countable.

- February 3rd 2009, 03:33 PMThePerfectHacker