can anyone do this question?
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can anyone do this question?
Hey
Do you know what Z6 means? What exactly is your question?
(1*1) mod 6 = 1
(1*2) mod 6 = 2
....
(1*5) mod 6 = 5
(2*1) mod 6 = (1*2) mod 6 = 2
(2*2) mod 6 = 4
(2*3) mod 6 = 6 mod 6 = 0
(2*4) mod 6 = 8 mod 6 = 2
(2*5) mod 6 = 10 mod 6 = 4
....
and so on.
Does it help?
Regards, Rapha
Hello, srk619!
Rapha is right . . .
You're expected to know what $\displaystyle \mathbb{Z}_6$ means.
If you don't, you shouldn't have been assigned this problem.
Quote:
Give the multiplication table for $\displaystyle \mathbb{Z}_6$
and hence find all solutions to: .$\displaystyle x^2 \,=\,3\:\text{ in }\mathbb{Z}_6$ or explain why there are none.
. . $\displaystyle \begin{array}{c||c|c|c|c|c|c|}
\times & 0&1&2&3&4&5 \\ \hline \hline
0 & 0&0&0&0&0&0 \\ \hline
1 & 0&1&2&3&4&5 \\ \hline
2 & 0&2&4&0&2&4 \\ \hline
3 & 0&3&0&3&0&3 \\ \hline
4 & 0&4&2&0&4&2 \\ \hline
5 & 0&5&4&3&2&1 \\ \hline\end{array}$
The values for $\displaystyle x^2$ are on the main diagonal,
. . where we see that: .$\displaystyle 3\cdot3 \:=\:3\text{ (mod 6)}$
Therefore: .$\displaystyle x = 3$
the question is part of Integers, Congruence arithmetic
its something like what is in the diagram
