can anyone do this question?

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- Feb 1st 2009, 05:22 AMsrk619logic sets help
can anyone do this question?

- Feb 1st 2009, 05:32 AMRapha
Hey

Do you know what Z6 means? What exactly is your question?

(1*1) mod 6 = 1

(1*2) mod 6 = 2

....

(1*5) mod 6 = 5

(2*1) mod 6 = (1*2) mod 6 = 2

(2*2) mod 6 = 4

(2*3) mod 6 = 6 mod 6 = 0

(2*4) mod 6 = 8 mod 6 = 2

(2*5) mod 6 = 10 mod 6 = 4

....

and so on.

Does it help?

Regards, Rapha - Feb 1st 2009, 05:54 AMSoroban
Hello, srk619!

Rapha is right . . .

You're expected to know what means.

If you don't, you shouldn't have been assigned this problem.

Quote:

Give the multiplication table for

and hence find all solutions to: . or explain why there are none.

. .

The values for are on the main diagonal,

. . where we see that: .

Therefore: .

- Feb 1st 2009, 06:48 AMsrk619
the question is part of Integers, Congruence arithmetic

its something like what is in the diagram