I'll help you with some of your questions:

1)

vi.

Everyone, in each fishing session, caught at least 10 fish (each in each session).

Let Fxz- x is in z fishing session.

Gxy-x caught y fish.

AxEyAz(Fxz->(Gxy&y>=10))

Not sure if I got this right, though.

3)

Determine thetruth setsfor the statement formsi:A'(x)^C(x);ii:B(x)-->A(x)

whereA(x): x^2-9<0,B(x):3x+3(greater than/equal to)0,C(x):|2x-5|>4

i) |2x-5|>4 means 2x-5>4 or 2x-5<-4 after rearranging this and combine it with the negation of A(x) which is x^2-9>=0 which means either x>=3 or x<=-3 you will get whatever answer it would be. for ii use material conditional where B(x)->A(x) is the same as: ~(B(x)&~A(x)).