An argument ,

is valid

if the conditional ,

is a tautology irrespective of the values of P,Q,R,S,T

And in our case let:

P= ~(1>0and 2+2=5) ,AND since 1>0 is true but 2+2=5 is false then 1>0 and 2+2=5 is false and hence ~(1>0 and 2+2=5) is true.

Q= ~

is also true since: if false implies false is true

R= (2+2=/=5------>2+3=6) IS false since 2+2=/= 5 is true but 2+3=6 is false

ALSO S=

is false,

Hence ,

is false ,but

T=

iS ALSO false and

Hence ,since false implying false is true ,the above argument is valid

SO by using the proper values of its constituents the argument can still be valid .