Do there exist functions f: R --> R such that for all I've a hunch it's no, as any squared term would be the same under x and -x, but I'm not sure how to provide a formal proof.
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Originally Posted by h2osprey Do there exist functions f: R --> R such that for all I've a hunch it's no, as any squared term would be the same under x and -x, but I'm not sure how to provide a formal proof. If is any function on and can you show that is an odd function?
Ah yes of course. Thanks!
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