Results 1 to 2 of 2

Math Help - Learning to count!

  1. #1
    Newbie
    Joined
    Oct 2008
    Posts
    13

    Learning to count!

    Lol, I am in an introductory section to the Addition and Multiplication Prinicples for counting sets/number of outcomes/possibilities.

    I am still having a hard time wrapping my head around how this all works

    Information:
    6 students; Matthew, Mark, Luke, John, Paul, and James.
    The officer positions; chairperson, secretary, and treasurer.

    Question:
    How many selections are there in which either Matt is chairperson or he is not an officer?

    What I came up with is this,

    As a chairperson -> there are 5 ways to choose 2nd position, 4 ways to choose 3rd position. Total 5 * 4 = 20 outcomes

    non-officer -> there are 5 ways to choose 1st position, 4 for 2nd position, & 3 for 3rd position Total 5 * 4 * 3 = 60 outcomes

    Using the Adding Principle 20 + 60 = 80 possible outcomes with matt and a chairperson or as a non-officer.


    Am I even close? Thanks
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Aug 2006
    Posts
    18,677
    Thanks
    1618
    Awards
    1
    That is correct. Way to go!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. What does 3^n count?
    Posted in the Discrete Math Forum
    Replies: 1
    Last Post: February 7th 2011, 01:59 AM
  2. Learning material
    Posted in the Advanced Statistics Forum
    Replies: 0
    Last Post: May 30th 2010, 03:51 AM
  3. triangular count
    Posted in the Discrete Math Forum
    Replies: 0
    Last Post: April 27th 2010, 06:22 AM
  4. Greedy Learning
    Posted in the Advanced Statistics Forum
    Replies: 0
    Last Post: March 2nd 2009, 02:51 AM
  5. How to count?
    Posted in the Math Challenge Problems Forum
    Replies: 3
    Last Post: October 7th 2008, 04:17 AM

Search Tags


/mathhelpforum @mathhelpforum