k1, k2, m1, m2 are cardinal numbers.

I need to prove that if k2>=k1 and m2>=m1, then k2m2>=k1m1

I know that i need to prove that this function f:AXC->BxD is injective, but then what?

Thanks for any help :-)

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- December 21st 2008, 07:18 AMJohn GQuestion in cardinality
k1, k2, m1, m2 are cardinal numbers.

I need to prove that if k2>=k1 and m2>=m1, then k2m2>=k1m1

I know that i need to prove that this function f:AXC->BxD is injective, but then what?

Thanks for any help :-) - December 23rd 2008, 10:35 PMGammaRight Track
I mean I think you are already pretty much done. I am guessing from your notation this is what you mean. You know since and then there must exist injective functions and . But then it is pretty obvious that defined by would also be injective. Just write out definitions and it is clear.