1. Equations satisfied by a and b

R encrypted as V implies

[ ]a + b ≡ [ ]mod 26

W encrypted as O implies [ ]a + b ≡ [ ]mod 26

2. Solutions for a and b

The value of a is [ ] (give least residue, mod 26, for a)

The value of b is [ ](give least residue, mod 26, for b)

3. Decryption map x ≡ (cy+d) mod 26

The value of c is [ ] (give least residue, mod 26, for c)

The value of d is [ ](give least residue, mod 26, for d)

I uploaded the encryption table.

So far i have

(i think)

1)

a)18a + 22b = ? mod 26

b)23a + 17b = ? mod 26

any ideas?