1. Equations satisfied by a and b
R encrypted as V implies
[ ]a + b ≡ [ ]mod 26
W encrypted as O implies [ ]a + b ≡ [ ]mod 26
2. Solutions for a and b
The value of a is [ ] (give least residue, mod 26, for a)
The value of b is [ ](give least residue, mod 26, for b)
3. Decryption map x ≡ (cy+d) mod 26
The value of c is [ ] (give least residue, mod 26, for c)
The value of d is [ ](give least residue, mod 26, for d)
I uploaded the encryption table.
So far i have
(i think)
1)
a)18a + 22b = ? mod 26
b)23a + 17b = ? mod 26
any ideas?