Hello, Urgently need some help with some Mathematical Communication. The question is: Show that the set of all odd square numbers {1,9,25,49,...} has cardinality ℵ0 [aleph-zero]. Any ideas?
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Originally Posted by Ellis Show that the set of all odd square numbers {1,9,25,49,...} has cardinality ℵ0 [aleph-zero]. The $\displaystyle k$-th non-negative odd number is $\displaystyle 2k-1$... Can you use this to find a bijection which maps $\displaystyle \mathbb{N}$ onto $\displaystyle \{1,9,25,49\ldots\}$ ?
What is the largest cardinality, because surely I can start with the cardinality of the set of all Real numbers and then work from there?
Originally Posted by Ellis What is the largest cardinality I don't know. because surely I can start with the cardinality of the set of all Real numbers and then work from there? I don't think so.
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