The start of the recurrence is OK since 0 < a1=1 < 4
i have a1=1
a(n+1) = (5an+4)/(an+2) for n>=1
need to prove by induction on n that 0<an<4 .
course of action would be?
then n is subscript and (n+1) also subscript , i think i need to get it into the form an+2 =A an+1 + B an
where A and B are some fixed numbers?