Prove that {1,...,10}X{1,...,15} is finite using only the definition of a finite set.
Defn.: "a set S is finite if either S is the empty set (well obviously not!) OR S is equivalent to the set {1,2,3,...,n} for some positive integer n.
Prove that {1,...,10}X{1,...,15} is finite using only the definition of a finite set.
Defn.: "a set S is finite if either S is the empty set (well obviously not!) OR S is equivalent to the set {1,2,3,...,n} for some positive integer n.
Consider $\displaystyle fa,b) \to \left[(a-1)+10\times (b-1) +1\right] $
Then the smallest value $\displaystyle f$ takes is $\displaystyle 1$, and the largest is $\displaystyle 150$, the image of distinct elements of $\displaystyle \{1,...,10\}X\{1,...,15\}$ are distinct. Thus we have $\displaystyle 150$ points in the range and $\displaystyle 150$ points in the image, and the image is: $\displaystyle \{1, ..., 150\}$.
Now turn this into a formal demonstration.
CB
Yes I do understand 1-to-1 & onto (mapping)...Most of our proofs in the last couple weeks have involved bijection....how does this relate to whether or not it's finite (or infinite)...I have already defined my domain & codomain (see previous entry)... f: domain--->codomain. What is f?...graphically it's a solid rectangle therefore how is it 1-to-1? (the cartesian product)....I need help!