A diagram is easy but with a pen

Let seeb)

and , so is surjective. But since has more elements than , can't be injective, so can't be bijective.

and , so is surjective. But since has more elements than , can't be injective, so can't be bijective. (yeah the proof is quite similar)

is the identity map on , it is bijective (i.e. injective and surjective).

That means is not injective. Furthermore, as has more elements than , so is not surjective, in conclusion, is "none of these".