Thread: COMBINATION PROBLEM - PLEASE HELP! I NEED ASAP

an urn contains 10 balls, bearing numbers 0 to 9
3 balls are randomly drawn with replacemet (without replacement).

By placing the numbers in row a in the order in which they are drawn, an integer 0 to 999 is formed. what is the probability that the number thus formed is divisible by 39. (regard 0 as being divisible by 39)

Originally Posted by sabrina87

an urn contains 10 balls, bearing numbers 0 to 9
3 balls are randomly drawn with replacemet (without replacement).

By placing the numbers in row a in the order in which they are drawn, an integer 0 to 999 is formed. what is the probability that the number thus formed is divisible by 39. (regard 0 as being divisible by 39)

The total number of integers so formed is (10)(9)(8) = 720.

How many of these integers (with distinct digits) are divisible by 39 .......? List them out:

039, 078,

156, 195, 234, 273, ......

So the probability will be .....