Prove that there is no quadratic polynomial p(x)=ax squared+bx+c, where a is not equal to 0 with p(-1)=2, p(0)=1, p(1)=3, p(2)=10
Use the first three values to solve for the coefficients, then substiture $\displaystyle x=2$ into the resulting quadratic to show that $\displaystyle p(2) \ne 10$.