Finding the number of partitions without consecutive integers in each block

Hello, I'd be really grateful for any help with this problem:

Show that the number of partitions of the set , such that no two consecutive integers appear in the same block of a partition is the Bell number .

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We know that the number of partitions of an -element set is . For example, if we have a 3-element set then ALL possible partitions of that set would be

and therefore . But in our problem, we are interested only in those partitions of a set which consist of blocks without any consecutive integers. So, in the above example, we would only be interested in partitions and - there are two of them, which is exactly the second Bell number, , and in fact there are only two partitions of a 2-element set, say, ; the first one is and the second one is .

Here, we have shown that the number of partitions of a 3-element set such that there are no consecutive integers in any block is . But, how to give a combinatorial proof that the number of such partitions of a -element set is ?

Many thanks! :)