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- Nov 4th 2008, 07:34 AM #1

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- Nov 4th 2008, 07:37 AM #2

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- Nov 4th 2008, 07:39 AM #3

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- Nov 4th 2008, 08:42 AM #4
The Captain gave the most straight forward and perfectly acceptable approach to the problem. as an alternative, you may want to use the contrapositive, then you only have to check 3 cases

Assume a and b are not both odd, then you have 3 cases:

(1) a is even but b is odd

(2) a is odd but b is even

(3) a and b are both even

in all cases, we have ab even, so the proof by contrapositive follows