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Math Help - Bijection Proofs

  1. #1
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    Bijection Proofs

    I'm trying to write a paper for one of my classes and I'm having trouble proving the following:

    A function f (A to B) is bijective if and only if there exists a function g (B to A) such that f composed with g equals 1B and g composed with f equals 1A.

    Also, I want to show that if a function g (B to A) exists such that f composed with g equals 1B then f (A to B) is bijective.

    I'm really stalled out. Any help would be great.
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  2. #2
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    Quote Originally Posted by OntarioStud View Post
    I'm trying to write a paper for one of my classes and I'm having trouble proving the following:

    A function f (A to B) is bijective if and only if there exists a function g (B to A) such that f composed with g equals 1B and g composed with f equals 1A.
    That is the inverse function (it exists)
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