Using the triangle inequality show and are in with , then open intervals centered at and centered at b, both with radius

so far all I have is

now I'm not sure if what I'm doing is right:

?

Printable View

- Sep 30th 2008, 09:25 PMlllllinequality proof
Using the triangle inequality show and are in with , then open intervals centered at and centered at b, both with radius

so far all I have is

now I'm not sure if what I'm doing is right:

? - Sep 30th 2008, 11:09 PMCaptainBlack
- Oct 3rd 2008, 11:03 PMlllll
I completely overlooked that part of the question. But I did found a prove for this statement but am still lost as to how it was done, even after asking my prof.

This is what I found:

suppose is in

which is apparently a contradiction.

If anyone could clarify this, it would help me out a lot. - Oct 3rd 2008, 11:08 PMCaptainBlack
- Oct 4th 2008, 03:22 PMlllll