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Math Help - Function Composition

  1. #1
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    Function Composition

    Suppose g: A-->C and h: B-->C.
    Prove: If h is bijective then there exists a function f: A-->B such that g=h(composed with)f.
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  2. #2
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    Quote Originally Posted by GoldendoodleMom View Post
    Suppose g: A-->C and h: B-->C.
    Prove: If h is bijective then there exists a function f: A-->B such that g=h(composed with)f.
    You know that h^{ - 1} :C \mapsto B. WHY?
    Consider the mapping h^{ - 1}  \circ g:A \mapsto B.
    Does that work?
    Now, I have left alot for you to explain.
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