Suppose g: A-->C and h: B-->C.

Prove: If h is bijective then there exists a function f: A-->B such that g=h(composed with)f.

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- Sep 14th 2008, 11:35 AMGoldendoodleMomFunction Composition
Suppose g: A-->C and h: B-->C.

Prove: If h is bijective then there exists a function f: A-->B such that g=h(composed with)f. - Sep 14th 2008, 12:28 PMPlato