Hello

Yes

Well, it's the same as just aboveA v A = U (or I think it might be A)

Just in case, A^A=A

See here : http://www.mathhelpforum.com/math-he...ns-proofs.htmlA ^ null set = A

A v null set = A

Make a diagram if you want to check by yourself !

uh ? just as beforeAnd finally if A is a subset of U,

Is:

null set v A = A

Yepcomplement of the null set = U

'welcome ^^Thanks for looking!