Thread: RC Network

Originally Posted by bobbyk

Sure. I'd love to, but I can't seem to.
5spice is a beautiful program whereby you can define networks and inputs and it will solve for the various outputs.

Well, I can't upload my 5spice files. I don't know why.
I have 5spice files for RC networks and their frequency response

Does 5spice display on the screen a diagram of the circuit?

If so [alt][PrintScreen] will capture the active window as a bitmap to
the clipboard. This can then be pasted into any graphics package and
trimmed to size and saved (as a .jpg is probably best). The saved file
can then be uploaded here from the manage attachments dialogue.

[PrintScreen] is in the top row of keys to the right of [f12].

This works for all versions ov windows. I don't know the equivalent
for *nix, or linux but they probably have something equivalent.

RonL

I haven't been able to post an attachment, but since the circuit is so simple
I'll just describe it for you.

It has an input terminal (1), an output terminal (2), a ground terminal (3), and an intermediate node (4).

Connect a 100K resistor between (1) and (2), a 1K resistor between (1) and
(4), a 1NF capacitor between (2) and (4), and a 0.1MF capacitor between
(4) and (3).

This circuit, as analyzed by 5Spice, has a maximum voltage gain from
input to output of 1.15 @ 1KHZ.

Originally Posted by bobbyk

I haven't been able to post an attachment, but since the circuit is so simple
I'll just describe it for you.

It has an input terminal (1), an output terminal (2), a ground terminal (3), and an intermediate node (4).

Connect a 100K resistor between (1) and (2), a 1K resistor between (1) and
(4), a 1NF capacitor between (2) and (4), and a 0.1MF capacitor between
(4) and (3).

This circuit, as analyzed by 5Spice, has a maximum voltage gain from
input to output of 1.15 @ 1KHZ.

Assuming NF is a nanno Farad, and MF a micro Farad is this what you have?:

No, the bottom capacitor is 0.1 microfarad rather than 1 microfarad. All
else is correct.
Thanks for responding, and I wish I could draw circuits like you do!

Originally Posted by bobbyk

No, the bottom capacitor is 0.1 microfarad rather than 1 microfarad. All
else is correct.
Thanks for responding, and I wish I could draw circuits like you do!

There is not much to it other that patience.

I spent some time looking for an online tool to do the job (I was at work
and I am reluctant to install stuff on work computers) but found nothing
to do the job, so I resorted to Power Point and basic drawing skills.

But I think your circuit does kill what I thought might be a viable approach
to the problem. Which was to decompose the circuit into a series of cascaded
T (or similar) networks, such that the transfer function was the product
of the individual elements (if that works).

RonL

I'm looking for a response from "pilonick". I haven't seen one.

It seems to me that posters who have been proved wrong should, out
of intellectial honesty, admit their mistakes, not to be vilified, but for
the rest of us to learn.

I may be wrong!

Originally Posted by bobbyk

I'm looking for a response from "pilonick". I haven't seen one.

It seems to me that posters who have been proved wrong should, out
of intellectial honesty, admit their mistakes, not to be vilified, but for
the rest of us to learn.

I may be wrong!

Your not wrong, but experience suggests this is not a common phenomenon
online where people are often anonymous, and so behave as if common
courtesy is not called for.

The last time pilonick posted was on the 7th of July, so hypothetically
he.they may not have seen your post. However exercising my super
powers as a moderator I know that the last time he visited MHF was
on the 23rd of July, which means he has probably seen your post.

RonL

It has occurred to me that, given an RC network having an over-unity voltage gain and an arbitrary number of resistors and capacitors of any
values, you can construct an ideal RC network having a voltage gain as large
as you please!
You merely cascade over-unity networks, each succeeding one having
the same time-constant, but having much larger impedance so as to not
to significantly load the preceeding one. The gains will, of course, multiply.