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Math Help - De Morgan's second law Proof

  1. #1
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    De Morgan's second law Proof

    Prove De Morgan's second law, ~(AB) = ~A v ~B, by applying De Morgan's first law to ~A and ~B.

    I think I know how to do it but I just need some clarification to justify my answer... Thanks
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  2. #2
    Math Engineering Student
    Krizalid's Avatar
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    Okay, then post your solution to see if it's correct.

    P.S.: that should be \sim(A\wedge B).
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  3. #3
    Super Member angel.white's Avatar
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    I don't understand how this can be used to prove anything since \sim(A\wedge B) \not{\equiv} \sim A ~\wedge \sim B.
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    similar problem done here
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