# Thread: Events and Sample space

1. ## Events and Sample space

Suppose that A & B are events in a sample space and that P(A) > (1/2) and P(B) > (1/2).

Prove that P(A "intersection" B) does not equal 0.

2. Originally Posted by ccdelia7
Suppose that A & B are events in a sample space and that P(A) > (1/2) and P(B) > (1/2).

Prove that P(A "intersection" B) does not equal 0.
Hint: $\displaystyle P(A \cup B) = P(A) + P(B) - P(A \cap B)$ and $\displaystyle P(A \cup B) \leq 1$

3. $\displaystyle 1 \ge P(A \cup B) = P(A) + P(B) - P(A \cap B) > \left( {1/2} \right) + \left( {1/2} \right) - P(A \cap B)$

Can you use that to finish?

4. similar to:

limit as n approaches zero, we know that P( A intersection B) must be greater than zero, though it may be close ( as the aforementioned limit). And thus, we see that it also cannot equal zero!

I think I may have been a bit vague, but let me know if that sounds right.

I think I have the right approach now.

Thanks

5. Originally Posted by ccdelia7
similar to:

limit as n approaches zero, we know that P( A intersection B) must be greater than zero, though it may be close ( as the aforementioned limit). And thus, we see that it also cannot equal zero!

I think I may have been a bit vague, but let me know if that sounds right.

I think I have the right approach now.

Thanks
I dont understand what you are saying

$\displaystyle 1 \ge P(A \cup B) = P(A) + P(B) - P(A \cap B) > \left( {1/2} \right) + \left( {1/2} \right) - P(A \cap B) \Rightarrow 0 < P(A \cap B)$