A coin is flipped "n" times. What is the probability that exactly"h" heads emerge? Explain.
- I just want to make sure that I'm doing this right.
I have the sample space as 2*n and the P(s)= H/(2*n).
Is this correct??
The probability of any particular distribution of n coin flips with order taken into account is $\displaystyle \frac{1}{2^n}$. So in order to determine the number of coin flips with exactly n coming up heads the formula is $\displaystyle {_8}C{_n}\cdot{\frac{1}{2^n}}$.