# Math Help - One-to-one function proof

1. ## One-to-one function proof

Any help at all is very very appreciated!!

Prove that if f:A->B and g:B->C are 1-1 functions then g o f:A->C

2. $g \circ f(a) = g \circ f(b) \Rightarrow \quad f(a) = f(b) \Rightarrow \quad a = b$