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Thread: One-to-one function proof

  1. April 27th 2008, 02:15 PM #1
    magicsam
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    One-to-one function proof

    Any help at all is very very appreciated!!

    Prove that if f:A->B and g:B->C are 1-1 functions then g o f:A->C
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  2. April 27th 2008, 02:59 PM #2
    Plato
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    g \circ f(a) = g \circ f(b) \Rightarrow \quad f(a) = f(b) \Rightarrow \quad a = b
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