# One-to-one function proof

• April 27th 2008, 02:15 PM
magicsam
One-to-one function proof
Any help at all is very very appreciated!!

Prove that if f:A->B and g:B->C are 1-1 functions then g o f:A->C
• April 27th 2008, 02:59 PM
Plato
$g \circ f(a) = g \circ f(b) \Rightarrow \quad f(a) = f(b) \Rightarrow \quad a = b$