# Formal Logic

• Apr 23rd 2008, 01:59 PM
Aryth
Formal Logic
A memory chip from a microcomputer has \$\displaystyle 2^4\$ bistable (ON-OFF) memory elements. What is the total number of ON-OFF configurations?

I have no idea where to start here. The book says:

\$\displaystyle 2^{2^2} = 2^{16}\$

Or something along those lines, the \$\displaystyle 2^{16}\$ is there, but I'm not sure that that's how they arranged the twos, either way, it confuses me.

Should it be:

\$\displaystyle 2^{4^2} = 2^{16}\$?
• Apr 23rd 2008, 02:05 PM
CaptainBlack
Quote:

Originally Posted by Aryth
A memory chip from a microcomputer has \$\displaystyle 2^4\$ bistable (ON-OFF) memory elements. What is the total number of ON-OFF configurations?

I have no idea where to start here. The book says:

\$\displaystyle 2^{2^2} = 2^{16}\$

Or something along those lines, the \$\displaystyle 2^{16}\$ is there, but I'm not sure that that's how they arranged the twos, either way, it confuses me.

Should it be:

\$\displaystyle 2^{4^2} = 2^{16}\$?

The number of configurations of \$\displaystyle N\$ bits is \$\displaystyle 2^N\$, in this case \$\displaystyle N=2^4\$, so the number of configurations is \$\displaystyle 2^{2^4}=2^{16}.\$

RonL
• Apr 23rd 2008, 02:06 PM
Aryth
That makes a lot more sense.

The book's answer threw me off.

Thanks.