Prove or disprove the following statement: Function composition is commutative; that is, if f : R --> R and g : R --> R, then (f o g)(x) = (g o f)(x) for all x in R. all the R are real numbers. i just don't know how to get the doubled bar R
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Originally Posted by jconfer Prove or disprove the following statement: Function composition is commutative; that is, if f : R --> R and g : R --> R, then (f o g)(x) = (g o f)(x) for all x in R. all the R are real numbers. i just don't know how to get the doubled bar R Think about these: .
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