Originally Posted by

**Soroban** Hello, spywx!

I hope I'm reading the problem correctly . . .

There are three possible outcomes . . .

(1) The three cards are of the same suit.

. . There is __one__ suit with an odd number of cards.

. . There are no suits with an even number of cards.

There are more *odd* suits.

(2) The three cards are: two of one suit, one of another.

. . There is __one__ suit with odd number of cards.

. . There is __one__ suit with an even number of cards.

It is a "tie".

(3) The three cards are of three different suits.

. . There is one card of the first suit.

. . There is one card of the second suit.

. . There is one card of the third suit.

. . There are __three__ suits with an odd number of each.

There are more *odd* suits.

It is more likely to have more suits with an **odd** number of cards.