Discrete!! Please Help. thanks in advance

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March 25th 2008, 08:49 AM
jas05s

Discrete!! Please Help. thanks in advance

Prove that there are no positive integer solutions to the equation x^2 + 8y = 3.
March 25th 2008, 09:23 AM
iknowone

Let $x$ be some positive integer. Then $x^2$ is a positive perfect square (integer). If $x > 1$ then $y = \frac{3-x^2}{8} < 0$ . If $x = 0 \text{ or } 1, y$ is not an integer.

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