# Discrete!! Please Help. thanks in advance

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• Mar 25th 2008, 09:49 AM
jas05s
Discrete!! Please Help. thanks in advance
Prove that there are no positive integer solutions to the equation x^2 + 8y = 3.
• Mar 25th 2008, 10:23 AM
iknowone
Let $x$ be some positive integer. Then $x^2$ is a positive perfect square (integer). If $x > 1$ then $y = \frac{3-x^2}{8} < 0$. If $x = 0 \text{ or } 1, y$ is not an integer.