$\displaystyle \begin{array}{l} f(0) = \sqrt {25} \\ f(n + 1) = 3f(n) + 1 \\ \end{array} $ Find F(n) for all positive numbers $\displaystyle \le$ 4 Would the answers be? f(1)=16 f(2)=49 f(3)=148 f(4)=445
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Originally Posted by Tally $\displaystyle \begin{array}{l} f(0) = \sqrt {25} \\ f(n + 1) = 3f(n) + 1 \\ \end{array} $ Find F(n) for all positive numbers $\displaystyle \le$ 4 Would the answers be? f(1)=16 f(2)=49 f(3)=148 f(4)=445 Yes.
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