$\displaystyle

\begin{array}{l}

f(0) = \sqrt {25} \\

f(n + 1) = 3f(n) + 1 \\

\end{array}

$

Find F(n) for all positive numbers $\displaystyle \le$ 4

Would the answers be?

f(1)=16

f(2)=49

f(3)=148

f(4)=445

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- Mar 14th 2008, 07:24 PMTallyCould you please clarify...
$\displaystyle

\begin{array}{l}

f(0) = \sqrt {25} \\

f(n + 1) = 3f(n) + 1 \\

\end{array}

$

Find F(n) for all positive numbers $\displaystyle \le$ 4

Would the answers be?

f(1)=16

f(2)=49

f(3)=148

f(4)=445 - Mar 14th 2008, 08:23 PMmr fantastic