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Math Help - Discrete/Logic

  1. #1
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    Discrete/Logic

    Heres the problem



    Heres my attempt. I'm not sure if I have done it correctly, if not, am I on the right track?



    Edit: My answer is meant to be true, not false
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  2. #2
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    \left[ {0 \in \mathbb{R}\backslash \mathbb{R}^ -  } \right]\left[ {\forall y \in \mathbb{R}\backslash \mathbb{R}^ -  } \right]\left( {0^2  < 1 + y} \right)
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  3. #3
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    What are these R symbols?

    Was I totally wrong? Is what you wrote the solution?
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  4. #4
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    Quote Originally Posted by g4me View Post
    What are these R symbols?
    Was I totally wrong? Is what you wrote the solution?
    Although that is no absolute set of symbols in mathematics some notations are widely accepted. The symbol \mathbb{R} is used to denote the real numbers. \mathbb{R}^+ denotes the positive reals and \mathbb{R}^- denotes the negative reals.
    Thus \mathbb{R}= \mathbb{R}^+ \cup \mathbb{R}^- \cup {0} so the nonnegative reals are \mathbb{R}\backslash \mathbb{R}^ -   = \mathbb{R}^ +   \cup \{ 0\} .

    As to the “Was I totally wrong?”, I really have no idea what you did. I cannot follow it. The symbolic statement reads “There is some nonnegative real number, x, having the property that for every real number y then x^2<y+1.
    You see that zero has that property; so does \frac {1} {2}.
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