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Thread: total order

  1. #1
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    total order

    Hi, I have question that I can't solve:

    R total orderr relation above A
    S total order relation above B

    T partial order relation above AB
    so that:
    (a1,b1)T(a2,b2) ⇔ (a1Ra2∧a1≠a2)∨(b1Sb2∧a1=a2)
    is T a total order realtion?


    many thanks !!
    Last edited by ronrong7; Sep 5th 2018 at 03:44 AM.
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  2. #2
    MHF Contributor

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    Re: total order

    Did you intend to have "$\displaystyle a_1\ne a_2$" twice rather than "$\displaystyle b_1\ne b_1$" the second times?
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  3. #3
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    Re: total order

    hi, sorry
    I intended to have a1=a2 at the second time.
    I edited my topic
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