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Thread: Re: Prove that a cube

  1. #1
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    Question Re: Prove that a cube

    Prove that a cube Qn includes a number of \[\binom{n}{k} \cdot 2^{n-k}\]Qk cubes.
    (We know that k<=n.)
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  2. #2
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    Re: Prove that a cube

    Quote Originally Posted by taleporos View Post
    Prove that a cube Qn includes a number of \[\binom{n}{k} \cdot 2^{n-k}\]Qk cubes.
    (We know that k<=n.)
    Please define your terms for those of us who aren't in your course. What does the $n$ mean for a cube? And the $k$? Or aren't you asking about ordinary cubes?
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  3. #3
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    Re: Prove that a cube

    Do you mean that a "Qn" cube has side length n?
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    Re: Prove that a cube

    Quote Originally Posted by Walagaster View Post
    Please define your terms for those of us who aren't in your course. What does the $n$ mean for a cube? And the $k$? Or aren't you asking about ordinary cubes?
    Quote Originally Posted by HallsofIvy View Post
    Do you mean that a "Qn" cube has side length n?
    This is a duplicate of the question here:
    Graph Theory Prove Problem (Please help)

    This question was originally asked at the end of another user's thread. Realizing the mistake, the user appears to have created a separate thread, and then someone split this post into its own thread.
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