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Thread: Probability question

  1. #1
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    Question Probability question

    Probability question-download-15-.png
    a) = 1/2
    b) = 1/2
    c)= P|AnB|/P|S| = 3 /2^3 = 3/8 AnB= 3
    Would you be able to consider part c) in positions for AnB e.g. position 1 _ position 2 _ etc.. or no?
    Last edited by inayat; May 18th 2018 at 04:27 PM.
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  2. #2
    MHF Contributor
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    Re: Probability question

    I don't understand what you've written for (c)

    $\begin{align*}

    &P[A \cap B] = \\ \\

    &P[\text{1 tail}] = \\ \\

    &\dbinom{3}{1} \left(\dfrac 1 2\right)^3 = \dfrac 3 8

    \end{align*}$

    If $A$ and $B$ are independent events then

    $P[A \cap B] = P[A]P[B]$

    from above

    $P[A\cap B] = \dfrac 3 8 \neq \dfrac 1 4 = \left(\dfrac 1 2 \right )^2 = P[A]P[B]$

    thus $A$ and $B$ are not independent.
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