98000 = 2^4 * 5^3 * 7^2
Compute the number of odd divisors of 98000
Im not what i need to do to start this
If $P=2^g\cdot3^h\cdot5^j\cdot7^k\cdot11^m\cdot13^n$ then $P$ has $(g+1)(h+1)(j+1)(k+1)(m+1)(n+1)$ factors. Of those $(h+1)(j+1)(k+1)(m+1)(n+1)$ and $h(g+1)(h+1)(j+1)(k+1)(m+1)(n+1)$ even.