Originally Posted by
HallsofIvy It is not "reflexive" because the base set contains "1" but the relationship does not contain "(1, 1)".
It is not "symmetric" because the relation contains "(a, 1)" but not "(1, a)".
It is "transitive" since every pair has second member "1" but no pair have first member "1". That is, the is no case where we have "(x, y)" and "(y, z)". The condition for "transitivity" is trivially satisfied.
For the graph, mark 8 points and label them "1", "2", "3", "4", "5", "a", "b", and "c". Then draw lines connecting "" and "1", "b" and "1", and "c" and "1".