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Thread: Boolean Simplification : Answer Check

  1. #1
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    Boolean Simplification : Answer Check

    Just checking my work. Please advise.

    (x'+z' )(x+y'+z' )

    =(x'x) + (x'y') + (x'z') + (z'x) + (z'y') + (z'z')
    =0 + x'y' + x'z' + z'x + z'y' + z'
    =x'y' + z' (x' + x) + z' (y' + 1)
    =x'y' + z' (1) + z' (1)
    =x'y' + (z' + z')
    =x'y' + z'
    Last edited by anpk05; Sep 5th 2017 at 06:06 PM.
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  2. #2
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    Re: Boolean Simplification : Answer Check

    I didn't go through the derivation but the final answer is correct.
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