How do you simplify X'Y+XY' boolean algebra expression?
Last edited by ramses4710; Aug 21st 2017 at 12:11 PM.
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assuming that $X,~Y$ are both functions of say $t$ $\dfrac {d}{dt}( XY )= X^\prime Y + X Y^\prime$ where $X^\prime = \dfrac{dX}{dt}$ and similarly for $Y$
How about in boolean algebra?
You are using a nonstandard notation. What is $X'$? Is that the same as "not $X$"? If so, then $X'Y+XY' = X\bigoplus Y = (X+Y)-XY$.
apologies, I missed the boolean algebra part, I just looked at the title. Does $X^\prime$ mean $\neg X$ or $!X$, i.e. "not X"? If so the expression is already minimal.