# Thread: Simplify X'Y+XY'

1. ## Simplify X'Y+XY'

How do you simplify X'Y+XY' boolean algebra expression?

2. ## Re: Simplify X'Y+XY'

assuming that $X,~Y$ are both functions of say $t$

$\dfrac {d}{dt}( XY )= X^\prime Y + X Y^\prime$

where

$X^\prime = \dfrac{dX}{dt}$ and similarly for $Y$

3. ## Re: Simplify X'Y+XY'

How about in boolean algebra?

4. ## Re: Simplify X'Y+XY'

You are using a nonstandard notation. What is $X'$? Is that the same as "not $X$"? If so, then $X'Y+XY' = X\bigoplus Y = (X+Y)-XY$.

5. ## Re: Simplify X'Y+XY'

apologies, I missed the boolean algebra part, I just looked at the title.

Does $X^\prime$ mean $\neg X$ or $!X$, i.e. "not X"?

If so the expression is already minimal.