Note that if f(x) = x^2, then Δ f(x) = 2x +1. Beginning with this observation, modify it to find that a function g(x) such that Δ g(x) = x+1 and g(0) = 0. Show calculations.
Haven't we been through this before?
Calculating Delta Δ
What is the exact meaning of $\Delta f(x)$ in the context of this problem and your prior problem posted in the above link?
Looking through other examples that used this delta, it appears that it is calculating the derivative. However, wouldn't the derivative of x^2 be 2x and I know that the derivative of a constant 0? I am confused about where the +1 is coming from.
Would g(x) simply equal x? Since g(0) would equal 0 in that case.
This was part of a problem set that our professor assigned. We have no tutors nor a textbook. Looking through my notes the only thing I have on it is that delta g(x) = g(x+1) -g(x)....... but I am not sure how to apply that knowledge.