1. ## Mathematical Induction

Hello.. Please help me to solve this question. I had tried to solve it but then I not get the same result if P(k+1) inserted in the question.
Thanks for help me.

3. ## Re: Mathematical Induction

The equation has a typo on the right hand side - it should be:

$\prod\limits _{r=1}^n (1+x^{2^r}) = \frac {1-x^{2^{n+1}}}{1-x^2}$

(note that the exponent in the numerator on the right hand side has 2^(n+1) in it, not 2^(r+1).

Using induction you first prove that this is true for n=1. Then show that if it's true for n=k it's also true for n = k+1.

Given: $\prod\limits _{r=1}^n (1+x^{2^r}) = \frac {1-x^{2^{n+1}}}{1-x^2}$, then

$\prod\limits _{r=1}^{k+1} (1+x^{2^r}) = \left( \prod\limits _{r=1} ^{k} (1+x^{2^r}) \right) (1+x^{2^{k+1}}) = \frac {1-x^{2^{k+1}}}{1-x^2} (1+x^{2^{k+1}})$

which equals $\frac {1-x^{2^{k+2}}}{1-x^2}$

4. ## Re: Mathematical Induction

thanks for the response. I really appreciate it.